If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2=24-29x
We move all terms to the left:
4x^2-(24-29x)=0
We add all the numbers together, and all the variables
4x^2-(-29x+24)=0
We get rid of parentheses
4x^2+29x-24=0
a = 4; b = 29; c = -24;
Δ = b2-4ac
Δ = 292-4·4·(-24)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-35}{2*4}=\frac{-64}{8} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+35}{2*4}=\frac{6}{8} =3/4 $
| 8a-6=90 | | 5^x-^6=125 | | p+20=100 | | 9/10x=15 | | 54+32x=-176 | | 8=y=5 | | 8=y=54 | | -10(-8+x)=90 | | -12x=-80 | | 5(2x+1)=22555 | | 67+7x+3=6x+6 | | x/12+3=63 | | 9+4h=93 | | 4b+2=34 | | 2=b-88/4 | | q/9+41=50 | | 2(s-40)=20 | | 4.5x=22.95 | | s+8/6=6 | | t/3-2=8 | | u+43/3=1 | | -19=b/7-25 | | m+6/10=3 | | 19=s/5+13 | | 3(t+11)=45 | | x2-87=-6 | | 100=10(w-83) | | 1/3x=9+1/3 | | x2+3x-9=2x | | s+21/4=8 | | s/6+6=10 | | 9/8=1/4x-1/4 |